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Simplifying c2 + 20 = 9c Reorder the terms: 20 + c2 = 9c Solving 20 + c2 = 9c Solving for variable 'c'. Reorder the terms: 20 + -9c + c2 = 9c + -9c Combine like terms: 9c + -9c = 0 20 + -9c + c2 = 0 Factor a trinomial. (4 + -1c)(5 + -1c) = 0Subproblem 1
Set the factor '(4 + -1c)' equal to zero and attempt to solve: Simplifying 4 + -1c = 0 Solving 4 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1c = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1c = 0 + -4 -1c = 0 + -4 Combine like terms: 0 + -4 = -4 -1c = -4 Divide each side by '-1'. c = 4 Simplifying c = 4Subproblem 2
Set the factor '(5 + -1c)' equal to zero and attempt to solve: Simplifying 5 + -1c = 0 Solving 5 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1c = 0 + -5 -1c = 0 + -5 Combine like terms: 0 + -5 = -5 -1c = -5 Divide each side by '-1'. c = 5 Simplifying c = 5Solution
c = {4, 5}
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